11x^2-16=-16x+6x^2

Solution for 11x^2-16=-16x+6x^2 equation:

11x^2-16=-16x+6x^2

We move all terms to the left:

11x^2-16-(-16x+6x^2)=0

We get rid of parentheses

11x^2-6x^2+16x-16=0

We add all the numbers together, and all the variables

5x^2+16x-16=0

a = 5; b = 16; c = -16;
Δ = b2-4ac
Δ = 162-4·5·(-16)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-24}{2*5}=\frac{-40}{10}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+24}{2*5}=\frac{8}{10}
=4/5
$